一个新版本的ubb转化程序

这段代码将用户输入的ubb代码转化为html格式，注意，需要Script Engine 5.0的支持(使用了RegExp对象)

注：pattern中使用()将知道regexp记忆搜索到的值，$1是第一个()，其余类推。但$2的语法并不被5.0版本的vbscript.dll所支持，我检查了自己机器上的版本（安装过ie 5.5)，发现vbscript.dll的版本为5.50.4629，最后修改日期为12月25日。该版本支持$1之类的语法，这个简单的改进使regexp的功能逐渐与perl的正则表达式靠近

function UBBCode(strContent)

dim objRegExp
Set objRegExp=new RegExp
objRegExp.IgnoreCase =true
objRegExp.Global=True
'url
objRegExp.Pattern="(\[URL\])(http://\S+?)(\[/URL\])"
strContent= objRegExp.Replace(strContent,"

1<a $2""="" href="" target="_blank">$2</a>

")
objRegExp.Pattern="(\[URL\])(\S+?)(\[/URL\])"
strContent= objRegExp.Replace(strContent,"

1<a $2""="" href="" http:="" target="_blank">$2</a>

")
'email
objRegExp.Pattern="(\[EMAIL\])(\S+@\S+?)(\[/EMAIL\])"
strContent= objRegExp.Replace(strContent,"

1<a href="" mailto:$2""="">$2</a>

objRegExp.Pattern="(\[IMG\])(\S+?)(\[/IMG\])"
strContent=objRegExp.Replace(strContent,"

1<img $2""="" src=""/>

objRegExp.Pattern="(\[QUOTE\])(.+?)(\[/QUOTE\])"
strContent=objRegExp.Replace(strContent,"

1<blockquote><font arial""="" face="" size="1" verdana,="">quote:</font><hr/>$2<hr/></blockquote>

objRegExp.Pattern="(\[i\])(.+?)(\[/i\])"
strContent=objRegExp.Replace(strContent,"

1<i>$2</i>

objRegExp.Pattern="(\[b\])(.+?)(\[/b\])"
strContent=objRegExp.Replace(strContent,"

1<b>$2</b>

")
set objRegExp=Nothing
UBBCode=strContent
end function
=-=====================
sub UBBCode {
my $ThePost = shift;
$ThePost =~ s/(\[URL\])(http://\S+?)(\[/URL\])/

 1<a href="$2" target="_blank">$2&lt;\/A&gt; /isg;   
 2$ThePost =~ s/(\\[URL\\])(\S+?)(\\[\/URL\\])/ <a href="http:\/\/$2" target="_blank">$2&lt;\/A&gt; /isg;   
 3$ThePost =~ s/(\\[EMAIL\\])(\S+\@\S+?)(\\[\/EMAIL\\])/ <a href="mailto:$2">$2&lt;\/A&gt; /isg;   
 4if (($UBBImages eq "ON") &amp;&amp; ($OverrideImages ne "yes")) {   
 5$ThePost =~ s/(\\[IMG\\])(\S+?)(\\[\/IMG\\])/ <img src="$2"/> /isg;   
 6}   
 7  
 8$ThePost =~ s/(\\[QUOTE\\])(.+?)(\\[\/QUOTE\\])/ <blockquote><font face="Verdana, Arial" size="1">quote:&lt;\/font&gt;<hr/>$2<hr/>&lt;\/BLOCKQUOTE&gt;/isg;   
 9$ThePost =~ s/(\\[i\\])(.+?)(\\[\/i\\])/<i>$2&lt;\/i&gt;/isg;   
10$ThePost =~ s/(\\[b\\])(.+?)(\\[\/b\\])/<b>$2&lt;\/b&gt;/isg;   
11return ($ThePost);   
12}</b></i></font></blockquote></a></a></a>