数据库中记录如下
023 1
023 2
024 1
023 3
023 4
024 2
023 1
..........
现在需要的目的是
id 是1的总数 不是1的总数
023 3 3
024 2 0
.......................
在线等，解决问题马上结账
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select id,sum(case 条件=1 then 1 else 0 end),sum(case 条件<>1 then 1 else 0 end) from table group by id
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select id,
sum(case when dd='1' then 1 else 0 end)as 是1的总数,
sum(case when dd<>'1' then 1 else 0 end)as 不是1的总数
from tbname
group by id
---------------------------------------------------------------
Select D.id,D.yes,D.no from(
SELECT C.id,A.YES,B.NO FROM Table C,
(select count() as yes from table where id='A00001') A,
(select count() as no from talble where id<>'A00001') B
) D
---------------------------------------------------------------
select id,sum(case when........end),sum(case when ......end)from table group by id