有这么一个表 pnamabbs_pri
rootid orderstr content time
1 null 21331 2003-01-08 19:30:10
2 null asdad 2003-01-08 19:39:10
3 null 213 2003-01-08 19:41:11
2 z 12312 2003-01-08 19:40:41
1 z asdes 2003-01-08 19:48:10
我想达到的效果是：
select rootid,max(time) as newesttime from pnamabbs_pri group by rootid order by newesttime
这样就出现了
rootid newesttime
1 2003-01-08 19:48:10
3 2003-01-08 19:41:11
2 2003-01-08 19:40:41
然后根据上面得出的结果（一定要根据上面得出的结果的rootid的顺序）
得到
rootid orderstr content time
1 null 21331 2003-01-08 19:30:10
1 z asdes 2003-01-08 19:48:10
3 null 213 2003-01-08 19:41:11
2 null asdad 2003-01-08 19:39:10
2 z 12312 2003-01-08 19:40:41
功能就是树状结构的bbs帖子的提升问题
原来我想用上面得到的排序后的结果和原来的表内联，可以行不通阿
sql说：除非同时指定了 TOP，否则 ORDER BY 子句在视图、内嵌函数、派生表和子查询中无效。
我该怎么办？
---------------------------------------------------------------
select A.* from pnamabbs_pri as A left join (
select rootid,max(time) as MaxTime from pnamabbs_pri
group by rootid) as B
on A.rootid = B.rootid
order by B.MaxTime desc, A.time
經過測試，沒有錯的！
---------------------------------------------------------------
select rootid,max(time) as newesttime from pnamabbs_pri group by rootid order by newesttime
出现的是：
rootid newesttime
----------- ---------------------------
2 2003-01-08 19:40:41.000
3 2003-01-08 19:41:11.000
1 2003-01-08 19:48:10.000
(3 row(s) affected)
select rootid,max(time) as newesttime from pnamabbs_pri group by rootid order by newesttime desc
出现的是：
rootid newesttime
----------- ---------------------------
1 2003-01-08 19:48:10.000
3 2003-01-08 19:41:11.000
2 2003-01-08 19:40:41.000
(3 row(s) affected)