请问如何查询条件是含有％的记录，oracle中有没有类似c中转义符的东西，谢谢。
---------------------------------------------------------------
SQL> select * from test3;
ID DOCTIME P1 NEWZYZ ZYZ1
---------- --------- ---------- -------------------- ----------
25 01-JUL-01 2002-01-01
26 01-JUL-01 1999-01-01
41 01-JUL-01 2000-01-01
6 24-SEP-02 1 asd sdf
7 24-SEP-02 2 adfsd dfsdf
8 24-SEP-02 4 asd%df dsfdsf%
6 01-JUL-01 2002-01-01
22 01-JUL-01 2001-01-01
8 rows selected.
SQL> select * from test3 where instr(newzyz,'%')>0;
ID DOCTIME P1 NEWZYZ ZYZ1
---------- --------- ---------- -------------------- ----------
8 24-SEP-02 4 asd%df dsfdsf%
---------------------------------------------------------------
对"%"字符用函数取ascii值，再用条件匹配。
---------------------------------------------------------------
select * from tabname where columnname like '%%' escape '';
---------------------------------------------------------------
ESCAPE关键字