ASP.NET中使用数据处理插入数据注意的问题

很多时候,我们都会习惯将数据库连接的初始化过程交给Page_Load去做,其实这样子有好处也有坏处,好处是单边问题的时候,这种方法很实用,坏处就是遇到多边的问题时,就种情况这不太好用了!例如下面的例子:

/// For Example:

 1<script language="C#" runat="server">   
 2SqlConnection mySqlCon;   
 3protected void Page_Load(Object Src,EventArgs E)   
 4{   
 5mySqlCon=new SqlConnection("server=localhost;uid=sa;pwd=sa;database=pubs"); //初始化过程   
 6if (!IsPostBack)   
 7BindGrid();   
 8}   
 9public void AddPublisher(Object sender, EventArgs E)   
10{   
11String myinsertCmd = "insert into publishers ( pub_id, pub_name, city, state, country ) values (@pubid,@pubname,@city,@state,@country)";   
12SqlCommand mySqlCom = new SqlCommand(myinsertCmd, mySqlCon); //初始化命令调用   
13//实现配套   
14mySqlCom.Parameters.Add(new SqlParameter("@pubid", SqlDbType.Char, 4));   
15mySqlCom.Parameters["@pubid"].Value = Pub_Id.Text;   
16mySqlCom.Parameters.Add(new SqlParameter("@pubname", SqlDbType.VarChar, 40));   
17mySqlCom.Parameters["@pubname"].Value = Pub_Name.Text;   
18mySqlCom.Parameters.Add(new SqlParameter("@city", SqlDbType.VarChar, 20));   
19mySqlCom.Parameters["@city"].Value = City.Text;   
20mySqlCom.Parameters.Add(new SqlParameter("@state", SqlDbType.Char, 2));   
21mySqlCom.Parameters["@state"].Value = State.Text;   
22mySqlCom.Parameters.Add(new SqlParameter("@country",SqlDbType.VarChar, 30));   
23mySqlCom.Parameters["@country"].Value = Country.Text;   
24//打开DB   
25mySqlCom.Connection.Open();   
26mySqlCom.ExecuteNonQuery();   
27Message.InnerHtml = "<b>已添加记录</b>
28";   
29mySqlCom.Connection.Close();   
30Pub_Id.Text = "";   
31Pub_Name.Text = "";   
32City.Text= "";   
33State.Text = "";   
34Country.Text = "";   
35BindGrid();   
36}   
37//子函数调用   
38public void BindGrid()   
39{   
40SqlDataAdapter mySqlCom = new SqlDataAdapter("select * from publishers where pub_id like '99%'", mySqlCon);   
41DataSet myds = new DataSet();   
42mySqlCom.Fill(myds, "publishers");   
43dgMyGrid.DataSource = myds.Tables["publishers"].DefaultView; dgMyGrid.DataBind();   
44}   
45</script>
1<h2>添加一个新的发行者:</h2>

发行者 ID 应以 99 打头,并包含 4 位数字

发行者 ID:

1<asp:textbox id="Pub_Id" runat="server"></asp:textbox>

姓名:

1<asp:textbox id="Pub_Name" runat="server"></asp:textbox>

城市:

1<asp:textbox id="City" runat="server"></asp:textbox>

省:

1<asp:textbox id="State" runat="server"></asp:textbox>

国家:

1<asp:textbox id="Country" runat="server"></asp:textbox>
1<asp:button id="Button1" onclick="AddPublisher" runat="server" text="提交"></asp:button>
1<span id="Message" runat="server"></span>
1<asp:datagrid id="dgMyGrid" runat="server"></asp:datagrid>

这样的例子初初看起来没有问题,调试也没报错,但在生成的页面添加数据后提交时就会报错,说什么属性不配套之类的话。是什么原因造成的呢!其实,这就是初始化过程在页面装载时造成的,但这里有个问题我始终没能搞清楚,就是既然是在页面初始化过程已经初始化过DB实例了,按道理来讲应该可以直接生成套用的啊,但好像没有!还是要把初始化过程放到具体的函数里面才能实现!看下面:
<

 1<script language="C#" runat="server">   
 2  
 3protected void Page_Load(Object Src,EventArgs E)   
 4{   
 5//页面装载过程中直接使用IF语句,其实什么也不加!   
 6if (!IsPostBack)   
 7BindGrid();   
 8}   
 9public void AddPublisher(Object sender, EventArgs E)   
10{   
11string strprovider="server=localhost;uid=sa;pwd=sa;database=pubs"; //构造初始化过程   
12SqlConnection mySqlCon=new SqlConnection(strprovider);   
13string myinsertCmd ="insert into publishers ( pub_id, pub_name, city, state, country ) values (@pubid,@pubname,@city,@state,@country)";   
14SqlCommand mySqlCom = new SqlCommand(myinsertCmd,mySqlCon); //初始化过程实现   
15mySqlCom.Parameters.Add(new SqlParameter("@pubid", SqlDbType.Char, 4));   
16mySqlCom.Parameters["@pubid"].Value = Pub_Id.Text;   
17mySqlCom.Parameters.Add(new SqlParameter("@pubname", SqlDbType.VarChar, 40));   
18mySqlCom.Parameters["@pubname"].Value = Pub_Name.Text;   
19mySqlCom.Parameters.Add(new SqlParameter("@city", SqlDbType.VarChar, 20));   
20mySqlCom.Parameters["@city"].Value = City.Text;   
21mySqlCom.Parameters.Add(new SqlParameter("@state", SqlDbType.Char, 2));   
22mySqlCom.Parameters["@state"].Value = State.Text;   
23mySqlCom.Parameters.Add(new SqlParameter("@country",SqlDbType.VarChar, 30));   
24mySqlCom.Parameters["@country"].Value = Country.Text;   
25mySqlCom.Connection.Open();   
26mySqlCom.ExecuteNonQuery();   
27Message.InnerHtml = "<b>已添加记录</b><br>";   
28mySqlCom.Connection.Close();   
29Pub_Id.Text = "";   
30Pub_Name.Text = "";   
31City.Text= "";   
32State.Text = "";   
33Country.Text = "";   
34BindGrid();   
35}   
36public void BindGrid() 子函数调用时同样也要初始化DB连接   
37{   
38string strprovider="server=dev;uid=sa;pwd=pauperboyboy;database=pubs";   
39SqlConnection mySqlCon=new SqlConnection(strprovider);   
40SqlDataAdapter mySqlCom = new SqlDataAdapter("select * from publishers where pub_id like '99%'",mySqlCon);   
41DataSet myds = new DataSet();   
42mySqlCom.Fill(myds, "publishers");   
43dgMyGrid.DataSource = myds.Tables["publishers"].DefaultView;   
44dgMyGrid.DataBind();   
45}   
46</script>
1<h2>添加一个新的发行者:</h2>
1<br/>

发行者 ID 应以 99 打头,并包含 4 位数字

1<br/>

发行者 ID:

1<asp:textbox id="Pub_Id" runat="server"></asp:textbox>

姓名:

1<asp:textbox id="Pub_Name" runat="server"></asp:textbox>

城市:

1<asp:textbox id="City" runat="server"></asp:textbox>
1<br/>

省:

1<asp:textbox id="State" runat="server"></asp:textbox>

国家:

1<asp:textbox id="Country" runat="server"></asp:textbox>
1<br/>
1<br/>
1<asp:button id="Button1" onclick="AddPublisher" runat="server" text="提交"></asp:button>
1<br/>
1<span id="Message" runat="server"></span>
1<br/>
1<asp:datagrid id="dgMyGrid" runat="server"></asp:datagrid>

>

经过这样修改后,我们才能在真正意义上实现数据的增加!但我也试了数据的删除和更新,在页面装载时直接赋于其初始化DB属性却没有问题,不知道是什么原因,知道的人给提个醒哦!谢谢 :)

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