xsl如何获取它解析的是哪个xml文件?

用xmldoc.transformNode(xsldoc)来获取数据时,如何在xsl文件里得到它解析的文件的url地址?
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if you are using XSLT, the information is not available to the stylesheet, but you can use msxsl:script to get node.ownerDocument.url

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