XMLHTTP的超时怎么设定？
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var xmlServerHttp = new ActiveXObject("Msxml2.ServerXMLHTTP");
var lResolve = 5 * 1000;
var lConnect = 5 * 1000;
var lSend = 15 * 1000;
var lReceive = 15 * 1000;
xmlServerHttp.setTimeouts(lResolve, lConnect, lSend, lReceive);
xmlServerHttp.open("GET", "http://localhost/sample.xml", false);
xmlServerHttp.send();
Example
Dim xmlServerHttp As New Msxml2.ServerXMLHTTP
Dim lResolve, lConnect, lSend, lReceive As Long
lResolve = 5 * 1000
lConnect = 5 * 1000
lSend = 15 * 1000
lReceive = 15 * 1000
xmlServerHttp.setTimeouts lResolve, lConnect, lSend, lReceive
xmlServerHttp.open "GET", "http://localhost/sample.xml", False
xmlServerHttp.send