** 在ASP.NET中实现多文件上传 **
在以前的Web应用中，上传文件是个很麻烦的事，现在有了.NET，文件上传变得轻而易举。下面的这个例子实现了多文件上传功能。可以动态添加输入表单，上传的文件数量没有限制。代码如下：
查看例子
MultiUpload.aspx
1@ Page Language="vb" AutoEventWireup="false" Codebehind="MultiUpload.aspx.vb" Inherits="aspxWeb.MultiUpload"
后代码：MultiUpload.aspx.vb
Public Class MultiUpload Inherits System.Web.UI.Page Protected WithEvents Upload As System.Web.UI.WebControls.Button Protected WithEvents MyTitle As System.Web.UI.WebControls.Label Protected WithEvents strStatus As System.Web.UI.WebControls.Label #Region " Web Form Designer Generated Code " 'This call is required by the Web Form Designer. Private Sub InitializeComponent() End Sub Private Sub Page_Init(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Init 'CODEGEN: This method call is required by the Web Form Designer 'Do not modify it using the code editor. InitializeComponent() End Sub #End Region Private Sub Page_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load MyTitle.Text = "
多文件上传
" Upload.Text = "开始上传" If (Me.IsPostBack) Then Me.SaveImages() End Sub Private Function SaveImages() As System.Boolean '遍历File表单元素 Dim files As System.Web.HttpFileCollection = System.Web.HttpContext.Current.Request.Files '状态信息 Dim strMsg As New System.Text.StringBuilder("上传的文件分别是：
") Dim iFile As System.Int32 Try For iFile = 0 To files.Count - 1 '检查文件扩展名字 Dim postedFile As System.Web.HttpPostedFile = files(iFile) Dim fileName, fileExtension As System.String fileName = System.IO.Path.GetFileName(postedFile.FileName) If Not (fileName = String.Empty) Then fileExtension = System.IO.Path.GetExtension(fileName) strMsg.Append("上传的文件类型：" + postedFile.ContentType.ToString() + "
") strMsg.Append("客户端文件地址：" + postedFile.FileName + "
") strMsg.Append("上传文件的文件名：" + fileName + "
") strMsg.Append("上传文件的扩展名：" + fileExtension + "
") '可根据扩展名字的不同保存到不同的文件夹 postedFile.SaveAs(System.Web.HttpContext.Current.Request.MapPath("images/") + fileName) End If Next strStatus.Text = strMsg.ToString() Return True Catch Ex As System.Exception strStatus.Text = Ex.Message Return False End Try End Function End Class